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Solution to: Missing Pages

Let the number of missing pages be n and the first missing page p+1. Then the pages p+1 up to and including p+n are missing, and n times the average of the numbers of the missing pages must be equal to 9808:

n×( ((p+1)+(p+n))/2 ) = 9808

In other words:

n×(2×p+n+1)/2 = 2×2×2×2×613

So:

n×(2×p+n+1) = 2×2×2×2×2×613

One of the two terms n and 2×p+n+1 must be even, and the other one must be odd. Moreover, the term n must be smaller than the term 2×p+n+1. It follows that there are only two solutions:

Because it is asked which pages (plural) are missing, the solution is: the pages 291 up to and including 322 are missing.


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