Solution to:
Odd Oranges
Assume the number of oranges is A. Then A1 is divisible by 3, 5, 7, and 9.
So, A1 is a multiple of 5×7×9 = 315 (note: 9 is also a multiple of 3, so 3 must not be included!).
We are looking for a value of N for which holds that 315×N + 1 is divisible by 11.
After some trying it turns out that the smallest N for which this holds is N = 3.
This means that the greengrocer has at least 946 oranges.
Note that for N = 14, 25, 36, etc. (so each time 11 more) it also holds that 315×N + 1 is divisible by 11.
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